Question
Use the imaginary number i to rewrite the expression below as a complex number. Simplify all radicals. \[ 1+\sqrt{-63} \]
Ask by Hall Joseph. in the United States
Jan 24,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( 1 + 3\sqrt{7}i \)
Solution
To rewrite the expression \( 1 + \sqrt{-63} \) as a complex number using the imaginary unit \( i \), follow these steps:
1. **Express the Square Root of a Negative Number:**
\[
\sqrt{-63} = \sqrt{63} \cdot i
\]
Here, \( i \) is the imaginary unit, defined by \( i^2 = -1 \).
2. **Simplify the Radical \( \sqrt{63} \):**
\[
\sqrt{63} = \sqrt{9 \times 7} = \sqrt{9} \times \sqrt{7} = 3\sqrt{7}
\]
3. **Combine the Results:**
\[
\sqrt{-63} = 3\sqrt{7} \cdot i
\]
4. **Write the Complete Complex Number:**
\[
1 + \sqrt{-63} = 1 + 3\sqrt{7}i
\]
**Final Answer:**
\[
1 + 3\,\sqrt{7}\,i
\]
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Mind Expander
To rewrite the expression \(1 + \sqrt{-63}\) as a complex number, we first recognize that \(\sqrt{-63}\) can be expressed in terms of \(i\). We know that \(\sqrt{-63} = \sqrt{63} \cdot \sqrt{-1} = \sqrt{63}i\). Now, simplifying \(\sqrt{63}\), we find that \(\sqrt{63} = \sqrt{9 \times 7} = \sqrt{9} \cdot \sqrt{7} = 3\sqrt{7}\). Thus, we can rewrite the expression as: \[ 1 + 3\sqrt{7}i. \] So the final answer is: \[ 1 + 3\sqrt{7}i. \]