Use the given function to complete parts a) through e) below. \( f(x)=-3(x-3)^{2}\left(x^{2}-4\right) \) a) Use the Leading Coefficient Test to determine the graph's end behavior The graph of \( f(x) \) rises left and falls night. The graph of \( f(x) \) falls left and falls right. The graph of \( f(x) \) falls left and rises right. b) Find the \( x \)-intercepts. The \( x \)-intercept(s) is/are \( \square \). \( \mathrm{\square} \). x . rises left and rises right. (Type an integer or a decimal. Use a comma to separate answers as needed )
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Mind Expander
To understand the end behavior of the function, let's take a quick trip down polynomial lane! The leading term of the function \( f(x) = -3(x-3)^2(x^2-4) \) is determined by expanding it out and looking at the highest degree term. Since we have a negative leading coefficient with an even degree, the graph will fall left and rise right - so the answer is: The graph of \( f(x) \) falls left and rises right! Now, for those elusive \( x \)-intercepts! To find the \( x \)-intercepts, we need to set \( f(x) = 0 \). From the function, this occurs when either \( (x-3)^2 = 0 \) or \( (x^2 - 4) = 0 \). This gives us \( x = 3 \) (with multiplicity 2) and \( x = 2, -2 \). So, the \( x \)-intercepts are: \( 3, 2, -2 \).