Question
upstudy study bank question image url

Use the given function to complete parts a) through e) below. \( f(x)=-3(x-3)^{2}\left(x^{2}-4\right) \) a) Use the Leading Coefficient Test to determine the graph's end behavior The graph of \( f(x) \) rises left and falls night. The graph of \( f(x) \) falls left and falls right. The graph of \( f(x) \) falls left and rises right. b) Find the \( x \)-intercepts. The \( x \)-intercept(s) is/are \( \square \). \( \mathrm{\square} \). x . rises left and rises right. (Type an integer or a decimal. Use a comma to separate answers as needed )

Ask by Nichols Bird. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

**a)** The graph of \( f(x) \) falls left and falls right. **b)** The \( x \)-intercepts are: \( -2, \ 2, \ 3 \).

Solution

Sure, let's work through parts **a)** and **b)** for the function: \[ f(x) = -3(x - 3)^2 (x^2 - 4) \] --- ### **a) Leading Coefficient Test: Determine the Graph's End Behavior** The **Leading Coefficient Test** helps us understand how the ends of the graph behave based on the leading term of the polynomial. 1. **Expand the Function to Identify the Leading Term:** \[ f(x) = -3(x - 3)^2 (x^2 - 4) \] First, expand \((x - 3)^2\): \[ (x - 3)^2 = x^2 - 6x + 9 \] Now, multiply this by \((x^2 - 4)\): \[ (x^2 - 6x + 9)(x^2 - 4) = x^4 - 6x^3 + 5x^2 + 24x - 36 \] Finally, multiply by \(-3\): \[ f(x) = -3x^4 + 18x^3 - 15x^2 - 72x + 108 \] The **leading term** is \(-3x^4\). 2. **Apply the Leading Coefficient Test:** - **Degree:** 4 (even) - **Leading Coefficient:** \(-3\) (negative) For polynomials with even degrees: - **Positive Leading Coefficient:** Both ends rise to \(+\infty\). - **Negative Leading Coefficient:** Both ends fall to \(-\infty\). Therefore, since the leading coefficient is negative and the degree is even: **End Behavior:** The graph **falls to the left** and **falls to the right**. --- ### **b) Find the \( x \)-Intercepts** To find the \( x \)-intercepts, set \( f(x) = 0 \) and solve for \( x \): \[ -3(x - 3)^2 (x^2 - 4) = 0 \] 1. **Set Each Factor Equal to Zero:** - \( (x - 3)^2 = 0 \) \(\Rightarrow x = 3\) (Multiplicity 2) - \( x^2 - 4 = 0 \) \(\Rightarrow x^2 = 4\) \(\Rightarrow x = 2 \) or \( x = -2 \) 2. **List the \( x \)-Intercepts:** \[ x = -2, \quad x = 2, \quad x = 3 \] **Note:** \( x = 3 \) is a repeated root, which means the graph **touches** the \( x \)-axis at this point but does not cross it. --- ### **Final Answers:** **a)** The graph of \( f(x) \) **falls left and falls right**. **b)** The \( x \)-intercepts are: \( -2, \ 2, \ 3 \).

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Mind Expander

To understand the end behavior of the function, let's take a quick trip down polynomial lane! The leading term of the function \( f(x) = -3(x-3)^2(x^2-4) \) is determined by expanding it out and looking at the highest degree term. Since we have a negative leading coefficient with an even degree, the graph will fall left and rise right - so the answer is: The graph of \( f(x) \) falls left and rises right! Now, for those elusive \( x \)-intercepts! To find the \( x \)-intercepts, we need to set \( f(x) = 0 \). From the function, this occurs when either \( (x-3)^2 = 0 \) or \( (x^2 - 4) = 0 \). This gives us \( x = 3 \) (with multiplicity 2) and \( x = 2, -2 \). So, the \( x \)-intercepts are: \( 3, 2, -2 \).

Related Questions

Latest Pre Calculus Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy