Q:
b. \( \left(-7 p^{3} q^{2}\right)^{2} \times 2 p q^{4} \)
Q:
2:364) Estimate. Which sign makes
the statement true?
\( \frac{1}{8} \times 50 ? 48 \)
\( > \)
Q:
\( \begin{array}{ll}2.3 & \text { Solve for } r \\ & 3^{r}+3^{3-r}=28\end{array} \)
Q:
Change the subject of the following formula to \( t \)
\( S=\frac{1}{2} g t^{2} \)
Q:
Question
Consider the function \( f(x) \) below. Over what open interval(s) is the function decreasing and concave up? Give your answer
in interval notation.
\[ f(x)=\frac{x^{4}}{4}+\frac{13 x^{3}}{3}+20 x^{2}+36 x-6 \]
Enter \( \varnothing \) if the interval does not exist.
Sorry, that's incorrect. Try again?
-
Q:
Use the elimination method to solve the system: \( \left\{\begin{array}{c}2 x+y=2 \\ 3 x-2 y=-4\end{array}\right. \)
Q:
\( \left. \begin{array} { l l } { A } & { T _ { n } = 4 n + 1 } \\ { B } & { T _ { n } = - 4 n + 9 } \\ { C . } & { T _ { n } = - 2 n + 7 } \\ { D } & { T _ { n } = 2 n + 3 } \end{array} \right. \)
Q:
\( \begin{array}{ll} & \text { Given: } \frac{2 m-3}{3}-3 \geq \frac{2 m}{6} \\ \text { 2.2.1 } & \text { Solve for } m \\ \text { 2.1.2 } & \text { Represent your solution graphically. }\end{array} \)
Q:
\begin{tabular}{l} Question \\ Use Newton's method to approximate the solution to the equation \( \frac{5}{x-6}=x+5 \). Use \( x_{0}=-4 \) as your starting value to \\ find the approximation \( x_{2} \) rounded to the nearest thousandth. \\ Provide your answer below: \\ \( \qquad x_{2} \approx \square \) \\ \hline\end{tabular}
Q:
Question
Use Newton's method with the specified initial approximation \( x_{0} \) to find \( x_{2} \), the third approximation to the root of the
equation given below. Round your answer to the nearest thousandth.
\[ f(x)=x^{3}-9 x-3, \quad x_{0}=1 \]
Provide your answer below:
\( x_{2} \approx \square \)
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