A manufacturer must test that his bolts are 2.00 cm long when they come off the assembly line. He must recalibrate his machines if the bolts are too long or too short. After sampling 169 randomly selected bolts off the assembly line, he calculates the sample mean to be 2.05 cm . He knows that the population standard deviation is 0.29 cm . Assuming a level of significance of 0.01 , is there sufficient evidence to show that the manufacturer needs to recalibrate the machines? Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places. Answer 2 Points

What is a scatter plot?

15. Suppose data collected for heights (in cms) of 390 cows were tabulated in a frequency distribution and the following results were obtained. fi: \( 6,25,48,72,116,60,38,22,3 \) CMI \( =112, \mathrm{CM} 2=117 \) where CMi ith class mark Determine: a) Class interval size (class width), Class limits, Class boundaries and class marks b) The less than cumulative frequency distribution c) The class intervals having the highest frequency d) Above which height do we find \( 50 \% \) of the cows? c) Below which height do we get \( 25 \% \) of the cows? Draw a) histogram b) a frequency polygon c) C. a less than ogive for the above data

Which sampling Which sampling method is better? Why? Which sampling method you might use in Assignment \# 2 (Marketing Dashboard)? Why?

15. Suppose data collected for heights (in cms) of 390 cows were tabulated in a frequency distribution and the following results were obtained. fi: \( 6,25,48,72,116,60,38,22,3 \) CMI \( =112, \mathrm{CM} 2=117 \) where CMi ith class mark Determine: a) Class interval size (class width), Class limits, Class boundaries and class marks b) The less than cumulative frequency distribution c) The class intervals having the highest frequency d) Above which height do we find \( 50 \% \) of the cows? c) Below which height do we get \( 25 \% \) of the cows? Draw a) histogram b) a frequency polygon c) C. a less than ogive for the above data

тета а, если: \( \sigma=3 ; n=36 ; \gamma=0,95 \) \( \sigma=3 ; n=36 ; \gamma=0,99 \) \( \sigma=3 ; n=36 ; \gamma=0,999 \)