ถ้า \( \frac{3 x-1}{12}=\frac{5}{6}- \) แล้ว \( 3 x \) มีค่าเท่ากับข้อใด

4. The factors of \( 2 x^{2}-8 \) are: \( 2\left(4 x^{2}\right) \) \( 2\left(x^{2}+4\right) \)

\( \left. \begin{array} { l l } { x ^ { 2 } - 4 } & { = y ^ { 2 } - 2 ^ { 2 } } \\ { y ^ { 2 } - 1 } & { = } \\ { 25 x ^ { 2 } - 36 } & { = } \\ { 16 - 81 a ^ { 2 } } & { = } \end{array} \right. \)

18. Fill in the blank with an appropriate inequality a. If \( x<-2 \), then \( 1-\mathrm{x} \) b. If \( \frac{1}{2}\left(3 x-\frac{2}{3}\right) \leq x+5 \), then \( x+\frac{7}{3} \) c. If \( 3 x-1>5 x-3 \), then \( 3 x \)

1) \( a^{2}-4 \)

Solve: \[ \frac{x-a}{x-b}+\frac{x-b}{x-a}=\frac{a}{b}+\frac{b}{a} \]