4. Uma PG infinita e decrescente, \( \left(?, \sqrt{\pi}, \frac{\pi}{2}, \frac{\pi^{\frac{3}{2}}}{4}, \cdots\right) \), sem o primeiro termo, tem como soma de todos os seus termos igual à \( \frac{4}{2-\sqrt{\pi}} \) e razão igual à \( \frac{\sqrt{\pi}}{2} \), qual é o valor do primeiro termo da PG.

Convert the point with polar coordinates \( \left(2, \frac{5 \pi}{6}\right) \) to Cartesian coordinates. Enter exact values. The point is: Get help: Video

Rewrite the Cartesian equation \( 2 x+3 y=8 \) as a polar equation. \( r(\theta)=\square \) Preview Enter theta for \( \theta \) if needed. Get help: Video

Convert the Cartesian coordinate \( (-5,-4) \) to polar coordinates, \( 0 \leq \theta<2 \pi, r>0 \) \( r=\square \) Preview \( \theta=\square \) Preview Get help: Video Video

Convert the Cartesian coordinate (2,5) to polar coordinates, \( 0 \leq \theta<2 \pi \) \( r=\square \) Preview Give the exact value for \( r \). \( \begin{array}{l}\text { Give } \theta \text { accurate to } 3 \text { decimal places. } \\ \text { Get help: Worked Example } 1\end{array} \)

9. (3 points) What kind of asymptotes(s) does the function \( y=\frac{4 x^{2}+3 x-1}{x^{2}-x}=\frac{(4 x-1)(x+1)}{x(x-1)} \) have? \( \begin{array}{ll}\text { A) Horizontal : } y=4 \text {, Vertical : } x=0, x=1 & \text { (B) Horizontal : } y=0 \text {, Vertical : } x=0, x=1 \\ \text { (C) Slant : } y=4 \text {, Vertical : } x=0 & \text { (D) Slant : } y=4 x-3 \text {, Vertical : } x=1\end{array} \)