Graph f, locate all points of disconlinuity, and discuss the behavior of fat these points. \[ f(x)=\left\{\begin{array}{ll} 1+x & \text { if } x<1 \\ 6-x & \text { if } x \geq 1 \end{array}\right. \] Discuss the behavior off at its point(s) of discontinuity. Find \( \mathrm{f}(\mathrm{x}) \) at any points of discontinuily Select the correct choico bolow and, if nocessary, fill in the answer box to completo your choice. A. At the point(s) of discontinuity, the value(s) of the function \( f(x) \) is/are \( \square \) (Use a comma lo separate answers as needed.) B. There are no points of discontinuity. Find \( \lim _{x \rightarrow c} f(x) \). where \( c \) is/are the poinl( \( (s) \) at which \( f(x) \) is dscontinuous. Select the correct choice below and, if necessary, fill in the answer box lo ccmplete your choice. A. \( \lim _{x \rightarrow c} f(x)= \) \( \square \) (Use a cormma to saparale answers as needed.) B. The limit does not exist
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The Deep Dive
Let’s first dive into the function f's behavior near the point of interest, which is at \( x = 1 \). If \( x < 1 \), the function follows the rule \( f(x) = 1 + x \). Thus, as you approach 1 from the left, the limit is \( \lim_{x \to 1^-} f(x) = 1 + 1 = 2 \). Now, when \( x \geq 1 \), \( f(x) = 6 - x \). Therefore, the limit as you approach from the right is \( \lim_{x \to 1^+} f(x) = 6 - 1 = 5 \). Since the left-hand limit (2) does not equal the right-hand limit (5), we have a point of discontinuity at \( x = 1 \). Now, when we look closer, \( f(1) = 6 - 1 = 5 \). This means that at the point of discontinuity \( x = 1 \), the function value \( f(1) = 5 \). To summarize: - At the point of discontinuity, the value(s) of the function \( f(x) \) is/are \( 5 \). - The limit as \( x \) approaches the point of discontinuity \( c = 1 \) does not match from both sides, so we conclude that \( \lim_{x \rightarrow 1} f(x) \) does not exist. So, the final answers are: A. At the point(s) of discontinuity, the value(s) of the function \( f(x) \) is/are \( 5 \) A. \( \lim_{x \to c} f(x) = \) does not exist