Question

As taxas de crescimento para uma população são descritas pela equação \( \frac{dP}{dt} = rP \) onde \( P \) é a população e \( r \) é a taxa de crescimento. Determine a função \( P(t) \) se \( P(0) = P_0 \).

Ask by French Savage. in Angola
Dec 09,2024

Real Tutor Solution

Tutor-Verified Answer

Answer

A função \( P(t) \) que descreve a população em função do tempo é \( P(t) = P_0 e^{rt} \).

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

Bonus Knowledge

Para resolver a equação diferencial \( \frac{dP}{dt} = rP \), podemos separá-las e integrar. Reescrevendo temos: \[ \frac{1}{P} \frac{dP}{dt} = r. \] Agora, integrando ambos os lados em relação ao tempo \( t \): \[ \int \frac{1}{P} dP = \int r \, dt. \] A integração nos dá: \[ \ln |P| = rt + C, \] onde \( C \) é a constante de integração. Aplicando a exponenciação: \[ |P| = e^{rt + C} = e^C e^{rt}. \] Definindo \( C' = e^C \), temos: \[ P = C' e^{rt}. \] Usando a condição inicial \( P(0) = P_0 \) para encontrar \( C' \): \[ P(0) = C' e^{r \cdot 0} = C' = P_0. \] Assim, a função que descreve a população em função do tempo é: \[ P(t) = P_0 e^{rt}. \]

Related Questions

Latest Calculus Questions

Explain why if a runner completes a \( 6.2-\mathrm{mi} \) race in 33 min , then he must have been running at exactly \( 11 \mathrm{mi} / \mathrm{hr} \) at least twice in the race. Assume the runner's speed at the finish line is zero. Select the correct choice and fill in the answer boxes to complete your choice. (Round to one decimal place as needed.) A. The average speed is \( \square \mathrm{mi} / \mathrm{hr} \). By the intermediate value theorem, the speed was exactly \( \square \mathrm{mi} / \mathrm{hr} \) at least twice. By MVT, all speeds between \( \square \) and \( \square \mathrm{mi} / \mathrm{hr} \) were reached. Because the initial and final speed was \( \square \mathrm{mi} / \mathrm{hr} \), the speed of \( 11 \mathrm{mi} / \mathrm{hr} \) was reached at least twice in the race. B. The average speed is \( \square \mathrm{mi} / \mathrm{hr} \). By MVT, the speed was exactly \( \square \mathrm{mi} / \mathrm{hr} \) at least twice. By the intermediate value theorem, the speed between \( \square \) and \( \square \mathrm{mi} / \mathrm{hr} \) was constant. Therefore, the speed of \( 11 \mathrm{mi} / \mathrm{hr} \) was reached at least twice in the race. C. The average speed is \( \square \mathrm{mi} / \mathrm{hr} \). By MVT, the speed was exactly \( \square \mathrm{mi} / \mathrm{hr} \) at least once. By the intermediate value theorem, all speeds between \( \square \) and \( \square \mathrm{mi} / \mathrm{hr} \) were reached. Because the initial and final speed was \( \square \mathrm{mi} / \mathrm{hr} \), the speed of \( 11 \mathrm{mi} / \mathrm{hr} \) was reached at least twice in the race.
Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy