Question
upstudy study bank question image url

1. Find the Jacobian of the following transformations. (a) \( x=u^{2}+u v, \quad y=u v^{2} \)

Ask by Mcfarlane Lowe. in the United States
Mar 31,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The Jacobian of the transformations is: \[ J = \begin{bmatrix} 2u + v & u \\ v^2 & 2uv \end{bmatrix} \]

Solution

To find the Jacobian of the given transformations, we need to calculate the partial derivatives of \( x \) and \( y \) with respect to \( u \) and \( v \). Given transformations: \[ x = u^2 + uv \] \[ y = uv^2 \] Let's calculate the partial derivatives: 1. Partial derivative of \( x \) with respect to \( u \): \[ \frac{\partial x}{\partial u} = 2u + v \] 2. Partial derivative of \( x \) with respect to \( v \): \[ \frac{\partial x}{\partial v} = u \] 3. Partial derivative of \( y \) with respect to \( u \): \[ \frac{\partial y}{\partial u} = v^2 \] 4. Partial derivative of \( y \) with respect to \( v \): \[ \frac{\partial y}{\partial v} = 2uv \] Now, we can calculate the Jacobian matrix using these partial derivatives: \[ J = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} = \begin{bmatrix} 2u + v & u \\ v^2 & 2uv \end{bmatrix} \] Therefore, the Jacobian of the given transformations is: \[ J = \begin{bmatrix} 2u + v & u \\ v^2 & 2uv \end{bmatrix} \]

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Bonus Knowledge

To find the Jacobian of the transformations \( x = u^2 + uv \) and \( y = uv^2 \), we need to compute the partial derivatives of \( x \) and \( y \) with respect to \( u \) and \( v \). The Jacobian \( J \) is given by the determinant of the following matrix: \[ J = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} \] Calculating the partial derivatives: 1. \( \frac{\partial x}{\partial u} = 2u + v \) 2. \( \frac{\partial x}{\partial v} = u \) 3. \( \frac{\partial y}{\partial u} = v^2 \) 4. \( \frac{\partial y}{\partial v} = 2uv \) Now, substituting these into the Jacobian matrix: \[ J = \begin{bmatrix} 2u + v & u \\ v^2 & 2uv \end{bmatrix} \] Next, we compute the determinant: \[ \text{det}(J) = (2u + v)(2uv) - (u)(v^2) \] Expanding this, we get: \[ = 4u^2v + 2uv^2 - uv^2 \] \[ = 4u^2v + uv^2 \] Thus, the Jacobian of the transformation is: \[ \text{det}(J) = u(4u + v) \]

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy