1. Find the Jacobian of the following transformations. (a) \( x=u^{2}+u v, \quad y=u v^{2} \)
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To find the Jacobian of the transformations \( x = u^2 + uv \) and \( y = uv^2 \), we need to compute the partial derivatives of \( x \) and \( y \) with respect to \( u \) and \( v \). The Jacobian \( J \) is given by the determinant of the following matrix: \[ J = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} \] Calculating the partial derivatives: 1. \( \frac{\partial x}{\partial u} = 2u + v \) 2. \( \frac{\partial x}{\partial v} = u \) 3. \( \frac{\partial y}{\partial u} = v^2 \) 4. \( \frac{\partial y}{\partial v} = 2uv \) Now, substituting these into the Jacobian matrix: \[ J = \begin{bmatrix} 2u + v & u \\ v^2 & 2uv \end{bmatrix} \] Next, we compute the determinant: \[ \text{det}(J) = (2u + v)(2uv) - (u)(v^2) \] Expanding this, we get: \[ = 4u^2v + 2uv^2 - uv^2 \] \[ = 4u^2v + uv^2 \] Thus, the Jacobian of the transformation is: \[ \text{det}(J) = u(4u + v) \]