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\( f ^ { m } ( z _ { 0 } + h ) - f ^ { m } ( z _ { 0 } ) = \frac { m ! } { 2 \pi i } \int _ { c } \frac { f ( z ) d z } { ( z - z _ { 0 } - h ) } - \frac { m ! } { 2 \pi i } \int _ { c } \frac { f ( z ) d z } { ( z - z _ { 0 } - h ) ^ { m + 1 } } \)

Ask by Powell Munoz. in Nepal
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The equation relates the difference in the \( m \)-th derivatives of a function \( f \) at two points to contour integrals of \( f(z) \).

Solution

To analyze the given equation, we will break it down step by step. The equation is: \[ f^{m}(z_{0} + h) - f^{m}(z_{0}) = \frac{m!}{2 \pi i} \int_{c} \frac{f(z) \, dz}{(z - z_{0} - h)} - \frac{m!}{2 \pi i} \int_{c} \frac{f(z) \, dz}{(z - z_{0} - h)^{m + 1}} \] ### Step 1: Understanding the Terms 1. **Left Side**: - \( f^{m}(z_{0} + h) \) and \( f^{m}(z_{0}) \) represent the \( m \)-th derivative of the function \( f \) evaluated at \( z_{0} + h \) and \( z_{0} \), respectively. 2. **Right Side**: - The right side consists of two integrals, both involving the function \( f(z) \) and a contour \( c \) around the point \( z_{0} \). ### Step 2: Analyzing the Integrals - The first integral: \[ \frac{m!}{2 \pi i} \int_{c} \frac{f(z) \, dz}{(z - z_{0} - h)} \] represents a residue calculation, which is related to the value of \( f(z) \) at the point \( z_{0} + h \). - The second integral: \[ -\frac{m!}{2 \pi i} \int_{c} \frac{f(z) \, dz}{(z - z_{0} - h)^{m + 1}} \] accounts for higher-order terms in the Taylor expansion of \( f \) around \( z_{0} + h \). ### Step 3: Interpretation The equation essentially states that the difference in the \( m \)-th derivatives of \( f \) at two points \( z_{0} + h \) and \( z_{0} \) can be expressed in terms of contour integrals involving \( f(z) \). This is a result of the Cauchy integral formula, which relates the values of analytic functions and their derivatives to integrals over contours. ### Conclusion This equation is a representation of how the \( m \)-th derivative of a function can be approximated using contour integrals. It highlights the relationship between the local behavior of the function around a point and its global properties as captured by the integrals. If you need further calculations or specific evaluations, please provide additional details or context!

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Extra Insights

Did you know that this equation essentially reflects the beauty of complex analysis and Cauchy's integral formula? Historically, complex function theory was developed in the 18th and 19th centuries by mathematicians like Cauchy and Riemann, laying the groundwork for modern engineering, physics, and even computer science! This specific formulation can relate to understanding the behavior of analytic functions in the neighborhood of a point, showcasing some of the multiple ways derivatives can be understood in the complex plane. In practical applications, this formula can be utilized in various fields including signal processing and fluid dynamics. For instance, engineers can analyze how small variations in a system (like electrical signals) would affect overall performance using similar integrals. It’s also a handy tool in numerical analysis, where approximating function values more efficiently can lead to significant computational savings. Just imagine harnessing complex functions to make your everyday tech work better!

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