Question

\( \int _{}^{}\tan (x)^{2} d x \)

Ask by Cummings Paul. in Turkey
Jan 21,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \int \tan^{2}(x) \, dx = \tan(x) - x + C \]

Solution

لحساب التكامل التالي: \[ \int \tan^{2}(x) \, dx \] نستخدم الهوية المثلثية: \[ \tan^{2}(x) = \sec^{2}(x) - 1 \] بالتالي: \[ \int \tan^{2}(x) \, dx = \int (\sec^{2}(x) - 1) \, dx = \int \sec^{2}(x) \, dx - \int 1 \, dx \] نعلم أن: \[ \int \sec^{2}(x) \, dx = \tan(x) + C \] \[ \int 1 \, dx = x + C \] بذلك نحصل على: \[ \int \tan^{2}(x) \, dx = \tan(x) - x + C \] حيث \( C \) هو ثابت التكامل.

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Beyond the Answer

To solve \( \int \tan^2(x) \, dx \), we can use the identity \( \tan^2(x) = \sec^2(x) - 1 \). Thus, the integral becomes: \[ \int \tan^2(x) \, dx = \int (\sec^2(x) - 1) \, dx = \int \sec^2(x) \, dx - \int 1 \, dx \] The integral of \( \sec^2(x) \) is \( \tan(x) \), and the integral of \( 1 \) is simply \( x \). Therefore, we have: \[ \int \tan^2(x) \, dx = \tan(x) - x + C \] where \( C \) is the constant of integration. In this playful integration adventure, remember that the trigonometric identities are your trusty sidekicks, helping you simplify expressions and tackle complex integrals with ease. Embracing these methods can transform what seems daunting into a delightful puzzle! If you're interested in diving deeper into integrals, consider exploring calculus textbooks or online platforms like Khan Academy. They'll provide a wealth of examples, from basic to advanced, ensuring you become a master of integral calculus!

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