For the angle \( \theta \) in standard position, determine the quadrant where the terminal side of \( \theta \) lies. \( \csc \theta>0 \) and \( \cot \theta>0 \) Quadrant:
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When considering the sign of \( \csc \theta \) and \( \cot \theta \), both being positive suggests that \( \sin \theta \) and \( \cos \theta \) are both positive. This occurs in the first quadrant, where all trigonometric ratios are positive. So, the terminal side of angle \( \theta \) lies in the first quadrant. Additionally, in the first quadrant, any angle ranging from \( 0 \) to \( 90 \) degrees has a positive sine and cosine. Thus, not only is \( \csc \theta \) positive (since it’s the reciprocal of the sine), but \( \cot \theta \), as the ratio of cosine to sine, also remains positive. This further confirms that \( \theta \) is indeed in the first quadrant.