A circle whose centre $$ (-2,5) $$ passes through point $$ P(10,10) $$. Find the equation of the is the form of $$ a x^{2}+b y^{2}+c x+d y+k=0 $$. Where ab, c $$ d $$ and $$ k $$ are constants.

Question

Burton Chadwick · Accepted Answer

The equation of the circle is $$ x^2 + y^2 + 4x - 10y - 140 = 0 $$.

A circle whose centre \( (-2,5) \) passes through point \( P(10,10) \). Find the equation of the is the form of \( a x^{2}+b y^{2}+c x+d y+k=0 \). Where ab, c \( d \) and \( k \) are constants.

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A circle whose centre \( (-2,5) \) passes through point \( P(10,10) \). Find the equation of the is the form of \( a x^{2}+b y^{2}+c x+d y+k=0 \). Where ab, c \( d \) and \( k \) are constants.

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