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To evaluate the integrals, we’ll tackle them one at a time.
(i) To evaluate
, we can use integration by parts. Let:
-
so that -
so that
Now, applying integration by parts:
So, the result is:
(ii) To evaluate the definite integral
, we can use substitution. Let:
Now we also need to express
in terms of
by rearranging:
Now, changing limits according to the substitution:
When
,
and when
,
. Plugging everything in:
This simplifies to:
This integral can be solved using the beta function or directly through evaluation techniques. The final answer can be simplified to arrive at a closed form.
Therefore, we find that:
So, the evaluations yield:
(i)
(ii)