Find the second derivative. $$ s=\frac{7 t^{3}}{3}+7 $$

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**Step 1. Compute the first derivative $$ s'(t) $$:**

Given
$$
s = \frac{7t^3}{3} + 7,
$$
differentiate term-by-term with respect to $$ t $$:

- For the term $$\frac{7t^3}{3}$$, use the power rule:
  $$
  \frac{d}{dt} \left( \frac{7t^3}{3} \right) = \frac{7}{3} \cdot 3t^2 = 7t^2.
  $$
- The derivative of the constant $$ 7 $$ is $$ 0 $$.

Thus,
$$
s'(t) = 7t^2.
$$

**Step 2. Compute the second derivative $$ s''(t) $$:**

Differentiate $$ s'(t) = 7t^2 $$ with respect to $$ t $$:

$$
s''(t) = \frac{d}{dt} \left( 7t^2 \right) = 7 \cdot 2t = 14t.
$$

**Final Answer:**

The second derivative is 
$$
s''(t) = 14t.
$$
The second derivative is $$ s''(t) = 14t $$.

Find the second derivative.

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