Solve each system by elimination. Check your answer. 11. \( \left\{\begin{array}{l}-x+y=-1 \\\ 2 x-y=0\end{array}\right. \)
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To solve the system by elimination, we start with the given equations: 1. \(-x + y = -1\) 2. \(2x - y = 0\) From the first equation, we can express \(y\) in terms of \(x\): \[ y = x - 1. \] Now, substitute this expression for \(y\) into the second equation: \[ 2x - (x - 1) = 0. \] This simplifies to: \[ 2x - x + 1 = 0, \] or \[ x + 1 = 0. \] Thus, \[ x = -1. \] Now, we substitute \(x = -1\) back into the equation for \(y\): \[ y = -1 - 1 = -2. \] The solution to the system is \(x = -1\) and \(y = -2\). So, the solution is \((-1, -2)\). To check our answer, we can substitute \(x\) and \(y\) back into both original equations: First, check the first equation: \[ -(-1) + (-2) = 1 - 2 = -1. \] (Correct!) Next, check the second equation: \[ 2(-1) - (-2) = -2 + 2 = 0. \] (Correct!) Both equations are satisfied, confirming our solution: \( \boxed{(-1, -2)} \).