Let $$ f(x)=x^{2}+4 x $$ (A) Find the slope of the secant line from $$ x=3 $$ to $$ x=9 $$ Slope of secant line $$ =\square $$

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To find the slope of the secant line for the function $$ f(x) = x^2 + 4x $$ between $$ x = 3 $$ and $$ x = 9 $$, use the formula for the slope of a secant line:

$$
\text{Slope} = \frac{f(9) - f(3)}{9 - 3}
$$

1. **Calculate $$ f(3) $$:**
   $$
   f(3) = 3^2 + 4 \times 3 = 9 + 12 = 21
   $$

2. **Calculate $$ f(9) $$:**
   $$
   f(9) = 9^2 + 4 \times 9 = 81 + 36 = 117
   $$

3. **Compute the slope:**
   $$
   \text{Slope} = \frac{117 - 21}{6} = \frac{96}{6} = 16
   $$

**Answer:**  
The slope of the secant line is $$ \boxed{16} $$.
The slope of the secant line is 16.

Let \( f(x)=x^{2}+4 x \) (A) Find the slope of the secant line from \( x=3 \) to \( x=9 \) Slope of secant line \( =\square \)

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