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3. \( \operatorname{Let} x=-\frac{5}{6} \) and \( y=\frac{4}{3} \quad \int_{-\frac{8}{8}}^{x} \)

Ask by Edwards Ortega. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

Cannot determine the value of the integral without knowing the function \( f(t) \).

Solution

To solve the integral \( \int_{-\frac{8}{8}}^{x} f(t) \, dt \) where \( x = -\frac{5}{6} \), we first need to clarify the function \( f(t) \) that we are integrating. Since the function is not provided, I will assume it is a general function \( f(t) \). 1. **Identify the limits of integration:** - The lower limit is \( -\frac{8}{8} = -1 \). - The upper limit is \( x = -\frac{5}{6} \). 2. **Set up the integral:** \[ \int_{-1}^{-\frac{5}{6}} f(t) \, dt \] 3. **Evaluate the integral:** Since we do not have a specific function \( f(t) \), we cannot compute a numerical value for the integral. However, if you provide a specific function \( f(t) \), I can help you evaluate the integral. Please provide the function \( f(t) \) for further assistance.

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Let’s compute the definite integral from \(-1\) to \(-\frac{5}{6}\). For simplicity, assume we're integrating a function like \(f(t) = t\). The integral \( \int_{-1}^{-\frac{5}{6}} t \, dt \) gives us: \[ = \left[ \frac{t^2}{2} \right]_{-1}^{-\frac{5}{6}} = \frac{(-\frac{5}{6})^2}{2} - \frac{(-1)^2}{2} = \frac{\frac{25}{36}}{2} - \frac{1}{2} = \frac{25}{72} - \frac{36}{72} = -\frac{11}{72}. \] Now, wouldn’t you love to know how integrals have been a cornerstone in mathematics since the days of Archimedes, who pioneered the use of infinitesimal areas? Isn’t it remarkable that concepts we've built upon for centuries still drive modern calculus today? You might also find yourself using definite integrals not just in academia but in real-world scenarios like calculating areas under curves or even for determining quantities like distance or mass. Just think about how engineers and scientists use these tools to predict everything from motion in physics to probabilities in statistics!

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