(b) $$ \lim _{x \rightarrow-\infty} \frac{8}{e^{x}+8}= $$ [NOTE: If needed, enter INF for $$ \infty $$ and MINF for $$ -\infty $$.]

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To evaluate the limit:

$$
\lim _{x \rightarrow -\infty} \frac{8}{e^{x} + 8}
$$

1. **Analyze the denominator as $$ x \rightarrow -\infty $$:**
   - $$ e^{x} $$ approaches $$ 0 $$ because $$ e^{x} $$ gets smaller as $$ x $$ becomes more negative.
   - Therefore, $$ e^{x} + 8 $$ approaches $$ 8 $$.

2. **Evaluate the limit:**
   - The expression simplifies to $$ \frac{8}{8} = 1 $$.

**Final Answer:**  
1
The limit is 1.

(b) \( \lim _{x \rightarrow-\infty} \frac{8}{e^{x}+8}= \) [NOTE: If needed, enter INF for \( \infty \) and MINF for \( -\infty \).]

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