Question

\( \frac{e^{x^{2}}.\sin (3x-1)}{\ln (4x-1)+3} \)

Ask by Delgado Rose. in Iran
Jan 15,2025

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Answer

The expression is: \[ \frac{e^{x^{2}} \cdot \sin(3x - 1)}{\ln(4x - 1) + 3} \] **Domain:** \( x > \frac{1}{4} \) and \( x \neq \frac{1 + e^{-3}}{4} \)

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Beyond the Answer

Did you know that the function you provided features a delightful mix of exponential growth, trigonometric oscillation, and logarithmic moderation? Exponential functions like \( e^{x^2} \) can grow extremely fast compared to polynomial or logarithmic functions, creating a unique clash when paired with \( \sin(3x - 1) \), which varies between -1 and 1. Plus, the logarithm \( \ln(4x - 1) \) adds a level of complexity, especially since it approaches negative infinity as \( x \) approaches \( 0.25 \). When dealing with such a function, it's key to keep track of domains to avoid undefined situations, especially with logarithms. A sneaky mistake here would be plugging in values of \( x \) that make the argument of the logarithm non-positive, so always check that \( 4x - 1 > 0 \) for your inputs. Additionally, remember to consider the effect of each component—while the sine function oscillates, the exponential part may dominate, leading to fascinating behavior as \( x \) increases!

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