Probability preguntas y respuestas

Jomework According to fightstats.com, American Airlines flights from Dallas to Chicago are on time \( 80 \% \) of the tin (a) Explain why this is a binomial experiment. (b) Determine the values of \( n \) and p . (c) Find and interpret the probability that exactly 9 flights are on time. (d) Find and interpret the probability that fewer than 9 flights are on time. (e) Find and interpret the probability that at least 9 flights are on time. (f) Find and interpret the probability that between 7 and 9 flights, inclusive, are on time. (a) Identify the statements that explain why this is a binomial experiment. Select all that apply.

A binomial probability experiment is conducted with the given parameters. Comput \[ n=11, p=0.3, x \leq 4 \] The probability of \( x \leq 4 \) successes is \( \square \). (Round to four decimal places as needed.)

3. A bag of marbles contains 9 red, 7 purple, 6 blue, and 3 yellow marbles. If pulling one marble out of the bag, what is the probability of choosing a purple marble?

A binomial probability experiment is conducted with the given parameters. Compute the probability of \( x \) successes in the \( n \) indepe \( n=10, p=0.2, x \leq 4 \) The probability of \( x \leq 4 \) successes is 6.9671 . (Round to four decimal places as needed.)

The pieces of candy in Paul's bag of candy have the following colors: 40 red \( \quad 30 \) blue \( \quad 30 \) yellow \( \begin{array}{l}\text { If Paul's friends selected a piece of candy at } \\ \text { random today, what is the probability that he will } \\ \text { select a red piece of candy? }\end{array} \)

20. A bag contains one red marble, one green marble, and one blue marble. You randomly pick a marble and keep it to play with. Then your friend picks a marble from the bag.

A bag contains one red marble and two green marbles. You randomly pick a marble and keep it to play with. Then your friend picks a marble from the bag.

Porording to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 . Suppos they sneeze. Complete parts (a) through (c). (a) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, exactly 5 do not cover their mouth when sneezing? The probability is 0.1945 . (Round to four decimal places as needed.) (b) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, fewer than 4 do not cover their mouth when sneezing? The probability is 0.6925 . (Round to four decimal places as needed.)

According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 , Suppose they sneeze. Complete parts (a) through (c). (a) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, exactly 5 do not cover their mouth when sneezing? The probability is 0.1945 . (Round to four decimal places as needed.) (b) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, fewer than 4 do not cover their mouth when sneezing? The probability is (Round to four decimal places as needed.)

8. A soccer player takes two penalty kicks in a game. Each attempt results in a goal or a miss.