Find the difference quotient $$ \frac{f(x+h)-f(x)}{h} $$, where $$ h \neq 0 $$, for the function below. $$ f(x)=-3 x^{2}-x+2 $$ Simplify your answer as much as possible. $$ \frac{f(x+h)-f(x)}{h}= $$

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Calculate or simplify the expression $$ \frac{-3(x+h)^{2}-(x+h)+2-(-3x^{2}-x+2)}{h} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{-3\left(x+h\right)^{2}-\left(x+h\right)+2-\left(-3x^{2}-x+2\right)}{h}$$
- step1: Remove the parentheses:
  $$\frac{-3\left(x+h\right)^{2}-\left(x+h\right)+2+3x^{2}+x-2}{h}$$
- step2: Calculate:
  $$\frac{-6xh-3h^{2}-h}{h}$$
- step3: Rewrite the fraction:
  $$-\frac{6xh+3h^{2}+h}{h}$$
- step4: Factor:
  $$-\frac{h\left(6x+3h+1\right)}{h}$$
- step5: Reduce the fraction:
  $$-\left(6x+3h+1\right)$$
- step6: Calculate:
  $$-6x-3h-1$$
The difference quotient $$ \frac{f(x+h)-f(x)}{h} $$ for the function $$ f(x)=-3x^{2}-x+2 $$ is $$ -6x-3h-1 $$.
The difference quotient is $$ -6x - 3h - 1 $$.

Find the difference quotient , where , for the function below.

Simplify your answer as much as possible.

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Find the difference quotient , where , for the function below. Simplify your answer as much as possible.