A roulette wheel has 34 slots around the rim; 32 slots are numbered from 1 to 32 . Half of these 32 slots are red, and the other half are black. The remaining 2 slots are numbered 0 and 00 and are green. As the roulette wheel is spun in one direction, a small ivory ball is rolled along the rim in the opposite direction. The ball has an equality likely chance of falling into any one of the 34 slots. Find the probabilities of the events listed in parts (a) through (d) below. a. Ball lands in a red slot The probability of the event that the ball lands in a red slot is \( \frac{8}{17} \). (Type an integer or a simplified fraction.) b. Ball lands on 0 or 32 The probability of the event that the ball lands on 0 or 32 is \( \frac{1}{17} \). (Type an integer or a simplified fraction.) c. Ball does not land on a number from 6 through 28 The probability of the event that the ball does not land on a number from 6 through 28 is (Type an integer or a simplified fraction.)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Mind Expander
The probability of the event that the ball does not land on a number from 6 through 28 can be found by considering the numbers outside that range. The numbers from 6 to 28 include 23 individual slots (6, 7, 8, ..., 28). Since there are 34 total slots, the slots that are not included in that range are: 1, 2, 3, 4, 5, 29, 30, 31, 32, 0, and 00. That gives us a total of 11 slots. Thus, the probability is \( \frac{11}{34} \). To summarize: - The ball lands in a red slot: \( \frac{8}{17} \) - The ball lands on 0 or 32: \( \frac{1}{17} \) - The ball does not land on a number from 6 through 28: \( \frac{11}{34} \)