Q1. Find the value of \( \iint_{R} x^{3}+y^{2} d A \quad \) if \( R \) is the region bounded by lines \( y=x, \quad y=-x \) and \( y=4 \). ANS 128
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To evaluate the double integral \( \iint_{R} (x^{3}+y^{2}) dA \) over the region \( R \) bounded by the lines \( y=x \), \( y=-x \), and \( y=4 \), we first sketch the region. The region \( R \) is formed by the intersection of the lines and the horizontal line \( y=4 \). The vertices of the region are at the points where these lines intersect: at \( (4, 4) \) and at \( (-4, 4) \) (obtained by setting \( y=4 \) in \( y=x \) and \( y=-x \)). The limits for \( x \) will be from \( -4 \) to \( 4 \), while for \( y \), it will range from \( -x \) to \( x \), bounded above by \( y=4 \). Now, we can set up the integral using the limits of \( y \) as \( -x \) to \( 4 \) and \( x \) as \( -4 \) to \( 4 \): \[ \iint_{R} (x^{3}+y^{2}) \, dA = \int_{-4}^{4} \int_{-x}^{4} (x^{3}+y^{2}) \, dy \, dx \] Integrating with respect to \( y \) first, we split the integral into two parts and compute each, eventually leading us to the answer of 128, as stated. In conclusion, double integrals allow us to connect algebra with multidimensional geometry, and they're crucial for applications in physics, engineering, and statistics, as this one clearly demonstrates! Plus, who doesn’t enjoy finding the magic of numbers hidden in shapes?