$$ \leftarrow \quad $$ Let $$ A=\left\{-9,-\frac{12}{4},-\frac{5}{8},-\sqrt{5}, 0, \frac{1}{4}, 5,6 \pi, 3, \sqrt{12}\right\} $$. List all the elements of $$ A $$ that belong to the set of integers.

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To determine which elements of the set $$ A $$ belong to the set of integers, we need to evaluate each element in $$ A $$ and check if it is an integer.

The set $$ A $$ is given as:
$$
A = \left\{-9, -\frac{12}{4}, -\frac{5}{8}, -\sqrt{5}, 0, \frac{1}{4}, 5, 6\pi, 3, \sqrt{12}\right\}
$$

Now, let's evaluate each element:

1. **$$-9$$**: This is an integer.
2. **$$-\frac{12}{4}$$**: This simplifies to $$-3$$, which is an integer.
3. **$$-\frac{5}{8}$$**: This is a fraction, not an integer.
4. **$$-\sqrt{5}$$**: This is an irrational number, not an integer.
5. **$$0$$**: This is an integer.
6. **$$\frac{1}{4}$$**: This is a fraction, not an integer.
7. **$$5$$**: This is an integer.
8. **$$6\pi$$**: This is an irrational number (since $$\pi$$ is irrational), not an integer.
9. **$$3$$**: This is an integer.
10. **$$\sqrt{12}$$**: This simplifies to $$2\sqrt{3}$$, which is an irrational number, not an integer.

Now, we can list the integers found in the set $$ A $$:
- $$-9$$
- $$-3$$
- $$0$$
- $$5$$
- $$3$$

Thus, the elements of $$ A $$ that belong to the set of integers are:
$$
\{-9, -3, 0, 5, 3\}
$$
The integers in set $$ A $$ are $$-9$$, $$-3$$, $$0$$, $$5$$, and $$3$$.

Let . List all the elements of that belong to the set of integers.

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