\[ f(x) = 3x + 4 \quad g(x) = 2x - 3 \] \[ \text{Find: } f \circ g(x) \]

To find \( f \circ g(x) \), we need to substitute the function \( g(x) \) into \( f(x) \). First, we calculate \( g(x) \): \[ g(x) = 2x - 3 \] Next, we substitute \( g(x) \) into \( f(x) \): \[ f(g(x)) = f(2x - 3) \] Now we substitute \( 2x - 3 \) into the function \( f \): \[ f(2x - 3) = 3(2x - 3) + 4 \] Now, distribute the 3: \[ = 6x - 9 + 4 \] Combine the constants: \[ = 6x - 5 \] Thus, \( f \circ g(x) = 6x - 5 \).