Multiply. $$ (v-7)(2 v+9) $$ $$ (v-7)(2 v+9)=\square $$ (Simplify your answer.)

Question

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To multiply the binomials $$(v - 7)$$ and $$(2v + 9)$$, follow these steps using the FOIL (First, Outer, Inner, Last) method:

1. **First:** Multiply the first terms in each binomial:
   $$
   v \times 2v = 2v^2
   $$

2. **Outer:** Multiply the outer terms:
   $$
   v \times 9 = 9v
   $$

3. **Inner:** Multiply the inner terms:
   $$
   -7 \times 2v = -14v
   $$

4. **Last:** Multiply the last terms in each binomial:
   $$
   -7 \times 9 = -63
   $$

Now, combine all these results:
$$
2v^2 + 9v - 14v - 63
$$

Combine like terms:
$$
2v^2 - 5v - 63
$$

So, the simplified form of the multiplication is:

$$
(v - 7)(2v + 9) = 2v^2 - 5v - 63
$$
$$ (v - 7)(2v + 9) = 2v^2 - 5v - 63 $$

Multiply. \( (v-7)(2 v+9) \) \( (v-7)(2 v+9)=\square \) (Simplify your answer.)