A suitcase is pulled 20 feet along a flat sidewalk with a constant upward force of 80 lb at an angle of \( 23^{\circ} \) with the horizontal. Calculate the work done. The work done is \( \square \) foot-pounds. (Round to the nearest foot-pound as needed.)
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To calculate the work done, we use the formula: \[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \] In this scenario, the force is 80 lb, the distance is 20 feet, and \(\theta\) (the angle with respect to the horizontal) is \(23^{\circ}\). First, we find the component of the force that acts in the direction of the distance: \[ \text{Work} = 80 \, \text{lb} \times 20 \, \text{ft} \times \cos(23^{\circ}) \] Calculating \(\cos(23^{\circ})\) approximately gives us 0.920. Now, substituting the values: \[ \text{Work} \approx 80 \times 20 \times 0.920 \approx 1472 \, \text{foot-pounds} \] Thus, the work done is approximately \( \text{1472} \) foot-pounds.