How many moles of gas are contained in a compressed air tank for scuba diving that has a volume of 6.5 L and a pressure of 230 . atm at \( 23 .{ }^{\circ} \mathrm{C} \) ? Be sure answer has the correct number of significant figures. Note: Reference the Fundamental constants table for additional information.

To determine the number of moles of gas in the tank, we can use the Ideal Gas Law, which states: \[ PV = nRT \] Where: - \( P \) is the pressure in atmospheres (230 atm) - \( V \) is the volume in liters (6.5 L) - \( n \) is the number of moles - \( R \) is the ideal gas constant (0.0821 L·atm/(K·mol)) - \( T \) is the temperature in Kelvin (°C + 273.15) First, convert the temperature: \[ T = 23 + 273.15 = 296.15 \, \text{K} \] Now, plug the values into the ideal gas equation to solve for \( n \): \[ n = \frac{PV}{RT} = \frac{(230 \, \text{atm}) (6.5 \, \text{L})}{(0.0821 \, \text{L·atm/(K·mol)}) (296.15 \, \text{K})} \] Calculating the values: \[ n = \frac{1495}{24.475215} \approx 61.0 \] The number of moles of gas contained in the compressed air tank is approximately 61.0 moles, expressed with three significant figures.