Consider the following two linear equations. $$ \begin{array}{l}8 x+2 y=-2 \ \text { Solve for the point of intersection using elimination }\end{array} $$

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It appears that only one linear equation was provided:

$$ 8x + 2y = -2 $$

To determine the **point of intersection** between two lines using the **elimination method**, we need **two distinct linear equations**. The point of intersection is the solution $$(x, y)$$ that satisfies both equations simultaneously.

**Here's what you need to do:**

1. **Provide a Second Equation:** Please provide the second linear equation so that we can use the elimination method to find the point where the two lines intersect.

**Example Scenario:**

If you have two equations, such as:

1. $$ 8x + 2y = -2 $$
2. $$ 4x - y = 3 $$

**We can solve them using elimination as follows:**

**Step 1: Align the Equations**
$$
\begin{align*}
8x + 2y &= -2 \quad \text{(Equation 1)} \
4x - y &= 3 \quad \text{(Equation 2)}
\end{align*}
$$

**Step 2: Make the Coefficients of $$y$$ Opposite**

Multiply Equation 2 by 2 to make the coefficient of $$y$$ in Equation 2 equal to $$-2$$:

$$
\begin{align*}
8x + 2y &= -2 \quad \text{(Equation 1)} \
8x - 2y &= 6 \quad \text{(Equation 2 multiplied by 2)}
\end{align*}
$$

**Step 3: Add the Equations to Eliminate $$y$$**

$$
(8x + 2y) + (8x - 2y) = -2 + 6 \
16x = 4 \
x = \frac{4}{16} \
x = \frac{1}{4}
$$

**Step 4: Substitute $$x$$ Back into One of the Original Equations to Find $$y$$**

Using Equation 2:

$$
4\left(\frac{1}{4}\right) - y = 3 \
1 - y = 3 \
-y = 2 \
y = -2
$$

**Solution:**

The point of intersection is $$\left( \frac{1}{4},\ -2 \right)$$.

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**Please provide the second equation**, and I'll be happy to help you find the point of intersection using the elimination method!
To find the point of intersection using elimination, you need two linear equations. Please provide the second equation so I can help solve for $$ x $$ and $$ y $$.

Consider the following two linear equations.

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