Solve for x $$ \begin{array}{l}8^{2 x-4}=\left(\frac{1}{16}\right)^{x-2} \ x=\end{array} $$

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Solve the equation $$ 8^{2x-4}=(\frac{1}{16})^{x-2} $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$8^{2x-4}=\left(\frac{1}{16}\right)^{x-2}$$
- step1: Rewrite the expression:
  $$2^{6x-12}=2^{-4x+8}$$
- step2: Set the exponents equal:
  $$6x-12=-4x+8$$
- step3: Move the expression to the left side:
  $$6x+4x=8+12$$
- step4: Add and subtract:
  $$10x=8+12$$
- step5: Add and subtract:
  $$10x=20$$
- step6: Divide both sides:
  $$\frac{10x}{10}=\frac{20}{10}$$
- step7: Divide the numbers:
  $$x=2$$
The solution to the equation $$8^{2x-4}=(\frac{1}{16})^{x-2}$$ is $$x=2$$.
$$ x=2 $$

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