What is the solution to \( \frac{1}{3}+\frac{5}{6}+\frac{1}{2} \) ? A \( \frac{7}{11} \) B \( 1 \frac{1}{6} \) C \( 1 \frac{4}{6} \) D 2

To find the solution to \( \frac{1}{3}+\frac{5}{6}+\frac{1}{2} \), we first need a common denominator, which would be 6. Rewriting the fractions: - \( \frac{1}{3} = \frac{2}{6} \) - \( \frac{5}{6} \) remains the same. - \( \frac{1}{2} = \frac{3}{6} \) Now we can add them: \[ \frac{2}{6} + \frac{5}{6} + \frac{3}{6} = \frac{10}{6} = 1 \frac{2}{6} = 1 \frac{1}{3} \] The incorrect options in the original list may lead to mix-ups, so keep an eye out! But as per the calculations, the result is much clearer, putting you comfortably with option B \( 1 \frac{1}{6} \).