Solve the equation. $$ p(15 p+17)=4 $$ The solution set is

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Solve the equation $$ p(15p+17)=4 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$p\left(15p+17ight)=4$$
- step1: Expand the expression:
  $$15p^{2}+17p=4$$
- step2: Move the expression to the left side:
  $$15p^{2}+17p-4=0$$
- step3: Factor the expression:
  $$\left(3p+4ight)\left(5p-1ight)=0$$
- step4: Separate into possible cases:
  $$\begin{align}&5p-1=0\&3p+4=0\end{align}$$
- step5: Solve the equation:
  $$\begin{align}&p=\frac{1}{5}\&p=-\frac{4}{3}\end{align}$$
- step6: Rewrite:
  $$p_{1}=-\frac{4}{3},p_{2}=\frac{1}{5}$$
The solution set for the equation $$p(15p+17)=4$$ is $$p_{1}=-\frac{4}{3}$$ and $$p_{2}=\frac{1}{5}$$.
The solutions are $$ p = -\frac{4}{3} $$ and $$ p = \frac{1}{5} $$.

Solve the equation.

The solution set is

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