Using the sign chart for \( f^{\prime \prime}(x)=-3(x+8)^{3}(x+4)^{2} \), and only that sign chart, what conclusions can be drawn about the graph of \( f \) on the interval \( x<-8 \) ? Answer \( \begin{array}{ll}\text { it is positive } & \text { it is negative } \\ \text { it is increasing } & \text { it is decreasing } \\ \text { is concave up } & \text { it is concave down } \\ \text { none of the above } & \text { Submit Answer }\end{array} \)
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To analyze the graph of \( f \) based on the given information about \( f^{\prime \prime}(x) \), we start by examining the sign of \( f^{\prime \prime}(x) \) for \( x < -8 \). Since \( f^{\prime \prime}(x) = -3(x+8)^{3}(x+4)^{2} \), we notice that for \( x < -8 \), both \( (x + 8) < 0 \) and \( (x + 4)^{2} > 0 \). Therefore, \( f^{\prime \prime}(x) < 0 \), indicating the function is concave down on the interval \( x < -8 \). Since \( f^{\prime \prime}(x) < 0 \), we can conclude that the first derivative \( f^{\prime}(x) \) is decreasing in that interval. However, we don't have enough information about \( f^{\prime}(x) \) itself in that specific range, as it could be either increasing or decreasing depending on the value of \( f^{\prime}(-8) \). Conclusively, we can say that: - It is concave down on \( x < -8 \). - We cannot definitively state whether it is increasing or decreasing without additional information on \( f^{\prime} \). So the answers would be: - It is concave down. - None of the above concerning increasing/decreasing.