Pregunta
How many atoms of calcium are in \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \) ?
Ask by Deleon Owen. in the United States
Feb 03,2025
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There are 3 calcium atoms in \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \).
Solución
In the chemical formula \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \), the subscript numbers indicate the number of each type of atom present in one formula unit of calcium phosphate.
- **Calcium (Ca):** The subscript **3** outside the calcium symbol \( \mathrm{Ca}_{3} \) indicates that there are **3 calcium atoms**.
- **Phosphate (\(\mathrm{PO}_{4}\)):** The subscript **2** outside the parentheses \( \left(\mathrm{PO}_{4}\right)_{2} \) means there are 2 phosphate groups. Each phosphate group contains 1 phosphorus (P) atom and 4 oxygen (O) atoms, but since the question is specifically about calcium atoms, we will focus on calcium.
**Summary:**
There are **3 calcium atoms** in one formula unit of \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \).
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In the formula \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \), there are 3 atoms of calcium (Ca) represented in the subscript. So, the total number of calcium atoms in the compound is 3. To clarify, the structure of \( \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \) tells us that for every two phosphate groups (PO₄), there are three calcium atoms present. So the answer is simply 3 atoms of calcium.
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