Use the basic integration rules to find or evaluate the integral. $$ \int \frac{100}{\sqrt{100-x^{2}}} d x $$

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Calculate the integral $$ \int \frac{100}{\sqrt{100-x^{2}}} d x $$.
Evaluate the integral by following steps:
- step0: Evaluate using formulas and rules:
  $$\int \frac{100}{\sqrt{100-x^{2}}} dx$$
- step1: Rewrite the expression:
  $$\int 100	imes \frac{1}{\sqrt{100-x^{2}}} dx$$
- step2: Use properties of integrals:
  $$100	imes \int \frac{1}{\sqrt{100-x^{2}}} dx$$
- step3: Evaluate the integral:
  $$100\arcsin\left(\frac{x}{10}ight)$$
- step4: Add the constant of integral C:
  $$100\arcsin\left(\frac{x}{10}ight) + C, C \in \mathbb{R}$$
The integral of $$ \frac{100}{\sqrt{100-x^{2}}} $$ with respect to $$ x $$ is $$ 100\arcsin\left(\frac{x}{10}ight) + C $$, where $$ C $$ is an arbitrary constant.
The integral $$ \int \frac{100}{\sqrt{100-x^{2}}} d x $$ equals $$ 100\arcsin\left(\frac{x}{10}ight) + C $$, where $$ C $$ is a constant.

Use the basic integration rules to find or evaluate the integral.

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