6. Solve for the variable in each equation. $$ L 27 $$ $$ \begin{array}{ll} ext { a. } \frac{j}{4.5}=-8.8 & ext { b. } k-\frac{7}{2}=8 \frac{1}{3}\end{array} $$

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6. Solve for the variable in each equation. $$ L 27 $$ $$ \begin{array}{ll}	ext { a. } \frac{j}{4.5}=-8.8 & 	ext { b. } k-\frac{7}{2}=8 \frac{1}{3}\end{array} $$

UpStudy AI · Accepted Answer

**a.**

We start with the equation
$$
\frac{j}{4.5} = -8.8.
$$
Multiply both sides by $$4.5$$ to isolate $$j$$:
$$
j = -8.8 \times 4.5.
$$
Calculating the product:
$$
-8.8 \times 4 = -35.2 \quad \text{and} \quad -8.8 \times 0.5 = -4.4.
$$
Thus,
$$
j = -35.2 - 4.4 = -39.6.
$$

**b.**

We start with the equation
$$
k - \frac{7}{2} = 8\frac{1}{3}.
$$
Convert the mixed number $$8\frac{1}{3}$$ to an improper fraction:
$$
8\frac{1}{3} = \frac{8 \times 3 + 1}{3} = \frac{25}{3}.
$$
Now, the equation becomes:
$$
k - \frac{7}{2} = \frac{25}{3}.
$$
Add $$\frac{7}{2}$$ to both sides to solve for $$k$$:
$$
k = \frac{25}{3} + \frac{7}{2}.
$$
Find a common denominator (which is $$6$$):
$$
\frac{25}{3} = \frac{50}{6} \quad \text{and} \quad \frac{7}{2} = \frac{21}{6}.
$$
Thus,
$$
k = \frac{50}{6} + \frac{21}{6} = \frac{71}{6}.
$$
**a.** $$ j = -39.6 $$ **b.** $$ k = \frac{71}{6} $$

Solve for the variable in each equation.

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