A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1430 feet, what
are the dimensions of the field?
The width of the field is
The length of the field is
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A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1430 feet, what
are the dimensions of the field?
The width of the field is
The length of the field is
Question Help:

Message instructor
Submit Question

UpStudy AI · Accepted Answer

To determine the dimensions of the rectangular field, let's follow these steps:

1. **Define Variables:**
   - Let $$ w $$ be the width of the field (in feet).
   - Since the length is twelve times the width, the length $$ l $$ is $$ 12w $$.

2. **Express the Perimeter:**
   - The formula for the perimeter $$ P $$ of a rectangle is:
     $$
     P = 2(l + w)
     $$
   - Given that the perimeter is 1430 feet:
     $$
     2(l + w) = 1430
     $$

3. **Substitute the Length:**
   - Replace $$ l $$ with $$ 12w $$:
     $$
     2(12w + w) = 1430
     $$
     $$
     2(13w) = 1430
     $$
     $$
     26w = 1430
     $$

4. **Solve for Width ($$ w $$):**
   $$
   w = \frac{1430}{26} = 55 \text{ feet}
   $$

5. **Find the Length ($$ l $$):**
   $$
   l = 12w = 12 \times 55 = 660 \text{ feet}
   $$

**Final Dimensions:**
- **Width of the field:** 55 feet
- **Length of the field:** 660 feet
The width of the field is 55 feet, and the length is 660 feet.

A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1430 feet, what
are the dimensions of the field?
The width of the field is
The length of the field is
Question Help: Message instructor
Submit Question

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A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1430 feet, what are the dimensions of the field? The width of the field is The length of the field is Question Help: Message instructor Submit Question

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Latest Algebra Questions

A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1430 feet, what
are the dimensions of the field?
The width of the field is
The length of the field is
Question Help: Message instructor
Submit Question