Pregunta
A chemist adds 260.0 mL of a
reaction flask. Calculate the millimoles of potassium iodide the chemist
has added to the flask. Round your answer to 2 significant digits.
reaction flask. Calculate the millimoles of potassium iodide the chemist
has added to the flask. Round your answer to 2 significant digits.
Ask by Daniels Blake. in the United States
Feb 15,2025
Solución de inteligencia artificial de Upstudy
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The chemist added 880 millimoles of potassium iodide to the flask.
Solución
To calculate the millimoles of potassium iodide (KI) added, follow these steps:
-
Convert the volume from milliliters to liters:
260.0 mL = 0.2600 L -
Use the molarity to find the number of moles:
Moles of KI = Molarity × Volume = 3.4 M × 0.2600 L = 0.884 moles -
Convert moles to millimoles:
1 mole = 1000 millimoles, so:
0.884 moles = 0.884 × 1000 = 884 millimoles -
Round to 2 significant digits:
884 rounded to 2 significant digits is 880.
Thus, the chemist has added 880 mmol of potassium iodide to the flask.
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Simplifique esta solución Bonus Knowledge
To find the millimoles of potassium iodide (KI) added to the flask, we can use the formula:
Millimoles (mmol) = Molarity (M) × Volume (L) × 1000.
First, convert the volume from mL to L:
260.0 mL = 0.260 L.
260.0 mL = 0.260 L.
Now calculate:
Millimoles = 3.4 M × 0.260 L × 1000 = 884.0 mmol.
Millimoles = 3.4 M × 0.260 L × 1000 = 884.0 mmol.
Rounding this to two significant digits gives us
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