\begin{tabular}{l|l}\( \begin{array}{l}\text { Solve the equation using the addition } \\ \text { property. Don't forget to perform a check. } \\ x-7.6=-5.2\end{array} \) & \( x=\square \) (Type a decimal number.) \\ \end{tabular}

To solve the equation \( x - 7.6 = -5.2 \) using the addition property, you need to isolate \( x \). You can do this by adding \( 7.6 \) to both sides of the equation. So, \( x - 7.6 + 7.6 = -5.2 + 7.6 \). Simplifying this gives \( x = 2.4 \). Next, let's check the solution by substituting \( x \) back into the original equation: \( 2.4 - 7.6 \). This equals \( -5.2 \), which confirms that our solution is correct. Thus, \( x = 2.4 \).