The areas of two similar parallelogram are in a ratio of . One side of the smaller parallelogram is 16 ft . Find the corresponding
side of the larger parallelogram. (Your answer will be numerical only).
Answer:

Question

The areas of two similar parallelogram are in a ratio of

. One side of the smaller parallelogram is 16 ft . Find the corresponding
side of the larger parallelogram. (Your answer will be numerical only).
Answer:

UpStudy AI · Accepted Answer

1. The ratio of the areas of the two parallelograms is given as $$4:49$$.  
2. For similar figures, the ratio of their areas equals the square of the ratio of their corresponding sides. Let the ratio of the corresponding sides be $$\frac{r}{1}$$. Then,  
   $$
   \left(\frac{r}{1}\right)^2 = \frac{49}{4}
   $$
3. Taking the square root of both sides:  
   $$
   \frac{r}{1} = \sqrt{\frac{49}{4}} = \frac{7}{2}
   $$
4. The corresponding side of the larger parallelogram can now be found by multiplying the side of the smaller parallelogram (16 ft) by the ratio $$\frac{7}{2}$$:  
   $$
   16 \times \frac{7}{2} = 56
   $$

Answer: 56
The corresponding side of the larger parallelogram is 56 ft.

The areas of two similar parallelogram are in a ratio of . One side of the smaller parallelogram is 16 ft . Find the corresponding
side of the larger parallelogram. (Your answer will be numerical only).
Answer:

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The areas of two similar parallelogram are in a ratio of . One side of the smaller parallelogram is 16 ft . Find the corresponding side of the larger parallelogram. (Your answer will be numerical only). Answer:

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The areas of two similar parallelogram are in a ratio of . One side of the smaller parallelogram is 16 ft . Find the corresponding
side of the larger parallelogram. (Your answer will be numerical only).
Answer: