of 5 The graph of $$ f(x)=x^{3} $$ is transformed by multiplying the function by a factor of $$ a=\frac{1}{4} $$. Identify the new coordinate for $$ x=4 $$ after $$ f(x) $$ is vertically compressed. (1 point) The new coordinates are ( $$ \square, \square) $$.

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After vertically compressing the function $$ f(x) = x^3 $$ by a factor of $$ \frac{1}{4} $$, the new function becomes:

$$
f_{\text{new}}(x) = \frac{1}{4}x^3
$$

To find the new coordinate for $$ x = 4 $$:

$$
f_{\text{new}}(4) = \frac{1}{4} \times 4^3 = \frac{1}{4} \times 64 = 16
$$

**The new coordinates are (4, 16).**
The new coordinates are (4, 16).

of 5
The graph of is transformed by multiplying the function by a factor of
. Identify the new coordinate for after is vertically compressed.
(1 point)
The new coordinates are ( .

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of 5 The graph of is transformed by multiplying the function by a factor of . Identify the new coordinate for after is vertically compressed. (1 point) The new coordinates are ( .