a) $$ \frac{63^{1-n} \cdot 7^{n-1} \cdot 81^{-1}}{4^{n+2} \cdot 36^{-n-1}} $$

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Calculate or simplify the expression $$ \frac{63^{1-n} \cdot 7^{n-1} \cdot 81^{-1}}{4^{n+2} \cdot 36^{-n-1}} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{63^{1-n}	imes 7^{n-1}	imes 81^{-1}}{4^{n+2}	imes 36^{-n-1}}$$
- step1: Factor the expression:
  $$\frac{9^{-n+1}	imes 7^{1-n}	imes 7^{n-1}	imes 81^{-1}}{4^{n+2}	imes 9^{-n-1}	imes 4^{-n-1}}$$
- step2: Reduce the fraction:
  $$\frac{9^{2}	imes 7^{1-n}	imes 7^{n-1}	imes 81^{-1}}{4^{n+2}	imes 4^{-n-1}}$$
- step3: Simplify:
  $$\frac{1}{4^{n+2}	imes 4^{-n-1}}$$
- step4: Multiply the terms:
  $$\frac{1}{4}$$
The simplified form of the expression $$ \frac{63^{1-n} \cdot 7^{n-1} \cdot 81^{-1}}{4^{n+2} \cdot 36^{-n-1}} $$ is $$ \frac{1}{4} $$ or 0.25.
The simplified form of the expression is $$ \frac{1}{4} $$ or 0.25.

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