Find the slope and $$ y $$-intercept of the line. (If an answer does not exist, enter DNE.) $$ x+4 y=0 $$ slope $$ y $$-intercept $$ \quad(x, y)=(\square) $$

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To find the **slope** and **$$ y $$-intercept** of the line given by the equation:

$$
x + 4y = 0
$$

**Step 1: Rewrite the equation in slope-intercept form ($$ y = mx + b $$)**

$$
x + 4y = 0 \
4y = -x \
y = -\frac{1}{4}x + 0
$$

**Step 2: Identify the slope ($$ m $$) and $$ y $$-intercept ($$ b $$)**

- **Slope ($$ m $$)**: The coefficient of $$ x $$ is $$ -\frac{1}{4} $$.
- **$$ y $$-intercept ($$ b $$)**: The constant term is $$ 0 $$, which means the $$ y $$-intercept is at the point $$ (0, 0) $$.

**Final Answer:**

- **Slope:** $$ -\frac{1}{4} $$
- **$$ y $$-intercept:** $$ (0, 0) $$
Slope: $$-\frac{1}{4}$$, $$ y $$-intercept: $$ (0, 0) $$.

Find the slope and -intercept of the line. (If an answer does not exist, enter DNE.)

slope
-intercept

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Find the slope and -intercept of the line. (If an answer does not exist, enter DNE.) slope -intercept