Responder
**Probability Question:**
50%
**Permutation Question:**
5040
Solución
Let's address both of your questions one by one:
---
### **1. Probability Question**
**Problem Statement:**
In a group of 200 car buyers:
- 60 bought alarm systems.
- 50 bought heated seats.
- 30 bought both an alarm system and heated seats.
**Question:**
If a car buyer chosen at random bought an alarm system, what is the probability they also bought heated seats?
**Options:**
- 25%
- 50%
- 20%
- 2%
**Solution:**
We need to find the probability that a buyer who bought an alarm system also bought heated seats. This is a conditional probability problem, where we calculate \( P(\text{Heated Seats} \mid \text{Alarm System}) \).
1. **Total buyers who bought an alarm system (A):** 60
2. **Buyers who bought both alarm systems and heated seats (A ∩ H):** 30
The conditional probability formula is:
\[
P(H \mid A) = \frac{P(A \cap H)}{P(A)}
\]
Plugging in the numbers:
\[
P(H \mid A) = \frac{30}{60} = 0.5 \text{ or } 50\%
\]
**Answer:** **50%**
---
### **2. Permutation Question**
**Problem Statement:**
How many words, with or without meaning, can be formed using the letters in the word "WARRIOR"?
**Options:**
- 2401
- 49
- 5040
- 343
**Solution:**
First, let's analyze the composition of the word "WARRIOR":
- Total letters: 7
- Letters and their frequencies:
- W: 1
- A: 1
- R: 3
- I: 1
- O: 1
Since there are repeating letters (specifically, the letter "R" appears 3 times), we'll use the formula for permutations of multiset:
\[
\text{Number of distinct arrangements} = \frac{n!}{n_1! \times n_2! \times \ldots \times n_k!}
\]
Where:
- \( n = \) total number of letters
- \( n_1, n_2, \ldots, n_k = \) frequencies of each repeating letter
Applying the values:
\[
\text{Number of distinct arrangements} = \frac{7!}{3!} = \frac{5040}{6} = 840
\]
However, **840** is not among the provided options. If we consider that there might be a typo and the word "WARRIOR" has only **two** "R"s instead of three, then:
\[
\text{Number of distinct arrangements} = \frac{7!}{2!} = \frac{5040}{2} = 2520
\]
Still, **2520** is not among the options either. Considering the closest possible answer provided:
- **5040** is the value of \(7!\), which assumes all letters are distinct.
Given the options and potential typographical errors in the question, **5040** seems to be the intended answer.
**Answer:** **5040**
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If there's any discrepancy in the second question regarding letter repetitions, please double-check the word "WARRIOR" for accurate calculation.
Revisado y aprobado por el equipo de tutoría de UpStudy
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