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The equation of the line with a slope of \( \frac{1}{5} \) passing through the point \( (-5, 8) \) is:
\[
y = \frac{1}{5}x + 9
\]
Solución
To find the equation of a line with a slope of \( \frac{1}{5} \) that passes through the point \( (-5, 8) \), you can use the **point-slope form** of a linear equation. Here's a step-by-step guide:
### 1. Point-Slope Form
The point-slope form of a line is given by:
\[
y - y_1 = m(x - x_1)
\]
Where:
- \( m \) is the slope of the line.
- \( (x_1, y_1) \) is a point on the line.
### 2. Plug in the Given Values
Given:
- Slope \( m = \frac{1}{5} \)
- Point \( (x_1, y_1) = (-5, 8) \)
Substitute these values into the point-slope form:
\[
y - 8 = \frac{1}{5}(x - (-5))
\]
\[
y - 8 = \frac{1}{5}(x + 5)
\]
### 3. Simplify to Slope-Intercept Form
To express the equation in the slope-intercept form \( y = mx + b \), where \( b \) is the y-intercept, follow these steps:
\[
y - 8 = \frac{1}{5}x + \frac{1}{5} \times 5
\]
\[
y - 8 = \frac{1}{5}x + 1
\]
\[
y = \frac{1}{5}x + 1 + 8
\]
\[
y = \frac{1}{5}x + 9
\]
### 4. Final Equation
The equation of the line in slope-intercept form is:
\[
\boxed{y = \frac{1}{5}x + 9}
\]
### 5. Alternative Forms
- **Standard Form:** \( Ax + By = C \)
To convert to standard form:
\[
y = \frac{1}{5}x + 9
\]
Multiply all terms by 5 to eliminate the fraction:
\[
5y = x + 45
\]
Rearrange:
\[
x - 5y + 45 = 0 \quad \text{or} \quad x - 5y = -45
\]
Typically, standard form is written with positive \( A \):
\[
\boxed{x - 5y = -45}
\]
- **Point-Slope Form:**
As derived earlier:
\[
\boxed{y - 8 = \frac{1}{5}(x + 5)}
\]
### 6. Graphical Representation
If you plot the line \( y = \frac{1}{5}x + 9 \):
- **Slope \( \frac{1}{5} \):** For every 5 units you move to the right (positive direction on the x-axis), the line rises by 1 unit.
- **Y-Intercept \( 9 \):** The line crosses the y-axis at the point \( (0, 9) \).
### 7. Verification
Ensure that the point \( (-5, 8) \) lies on the line:
\[
y = \frac{1}{5}x + 9
\]
\[
8 = \frac{1}{5}(-5) + 9
\]
\[
8 = -1 + 9
\]
\[
8 = 8 \quad \checkmark
\]
The calculation confirms that the point \( (-5, 8) \) satisfies the equation.
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