Solve the equation. Express numbers in exact simplest form. $$ 3 q(q+7)=-36 $$

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Solve the equation $$ 3q(q+7)=-36 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$3q\left(q+7ight)=-36$$
- step1: Expand the expression:
  $$3q^{2}+21q=-36$$
- step2: Move the expression to the left side:
  $$3q^{2}+21q+36=0$$
- step3: Factor the expression:
  $$3\left(q+3ight)\left(q+4ight)=0$$
- step4: Divide the terms:
  $$\left(q+3ight)\left(q+4ight)=0$$
- step5: Separate into possible cases:
  $$\begin{align}&q+3=0\&q+4=0\end{align}$$
- step6: Solve the equation:
  $$\begin{align}&q=-3\&q=-4\end{align}$$
- step7: Rewrite:
  $$q_{1}=-4,q_{2}=-3$$
The solutions to the equation $$3q(q+7)=-36$$ are $$q=-4$$ and $$q=-3$$.
The solutions are $$q=-4$$ and $$q=-3$$.

Solve the equation. Express numbers in exact simplest form.

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