\( \quad \frac{5}{6}+\frac{1}{9}= \) a2 \( 15 / 18 \) b) \( 17 / 18 \) (c) \( 4 / 18 \) d) \( 16 / 18 \)

To find the sum of \( \frac{5}{6} + \frac{1}{9} \), we first need a common denominator. The least common multiple of 6 and 9 is 18. So, we convert the fractions: \( \frac{5}{6} \) becomes \( \frac{15}{18} \) and \( \frac{1}{9} \) becomes \( \frac{2}{18} \). Adding these gives us \( \frac{15}{18} + \frac{2}{18} = \frac{17}{18} \). So the correct answer is b) \( 17 / 18 \). When dealing with fractions, it's important to remember to convert them to a common denominator before adding or subtracting. A common mistake is to simply add the numerators and denominators of the fractions without finding the least common multiple. Always check your denominators first!