2.1 For the point $$ P(14,9) $$ and $$ Q(21,14) $$, find the distance $$ d(P, Q) $$ and the coordinates of the midpoint $$ M $$ of the segment $$ P Q $$.

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To find the distance between two points $$ P(x_1, y_1) $$ and $$ Q(x_2, y_2) $$, we can use the distance formula:

$$ d(P, Q) = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $$

Given points $$ P(14, 9) $$ and $$ Q(21, 14) $$, we can substitute the coordinates into the formula to find the distance $$ d(P, Q) $$.

To find the coordinates of the midpoint $$ M $$ of the segment $$ PQ $$, we can use the midpoint formula:

$$ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) $$

Let's calculate the distance and the coordinates of the midpoint.
Calculate the value by following steps:
- step0: Calculate:
  $$\sqrt{\left(21-14\right)^{2}+\left(14-9\right)^{2}}$$
- step1: Subtract the numbers:
  $$\sqrt{7^{2}+\left(14-9\right)^{2}}$$
- step2: Subtract the numbers:
  $$\sqrt{7^{2}+5^{2}}$$
- step3: Add the numbers:
  $$\sqrt{74}$$
The distance between points $$ P(14, 9) $$ and $$ Q(21, 14) $$ is approximately $$ 8.602325 $$.

Now, let's calculate the coordinates of the midpoint $$ M $$ of the segment $$ PQ $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{\left(14+21\right)}{2}$$
- step1: Remove the parentheses:
  $$\frac{14+21}{2}$$
- step2: Add the numbers:
  $$\frac{35}{2}$$
Calculate or simplify the expression $$ (9+14)/2 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{\left(9+14\right)}{2}$$
- step1: Remove the parentheses:
  $$\frac{9+14}{2}$$
- step2: Add the numbers:
  $$\frac{23}{2}$$
The coordinates of the midpoint $$ M $$ of the segment $$ PQ $$ are $$ (17.5, 11.5) $$.
The distance between points $$ P(14, 9) $$ and $$ Q(21, 14) $$ is approximately $$ 8.602325 $$, and the midpoint $$ M $$ of the segment $$ PQ $$ is $$ (17.5, 11.5) $$.

2.1
For the point and , find the distance and the coordinates of the midpoint of the
segment .

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2.1 For the point and , find the distance and the coordinates of the midpoint of the segment .