Pregunta
The U.S. Weather Bureau has a station on Mauna Loa in Hawaii that has measured carbon dioxide levels since 1959. At that time, there were 314 parts per million of carbon dioxide in the atmosphere. In 2005 , the figure was 389 parts per million. Find the increase in carbon dioxide levels and the percent of increase. Round to the nearest tenth of a percent. Increase carbon dioxide levels: Percent increase:
Ask by Campbell Boone. in the United States
Feb 03,2025
Solución de tutoría real
Respuesta verificada por el tutor
Responder
Increase in carbon dioxide levels: 75 parts per million
Percent increase: 23.9%
Solución
Increase carbon dioxide levels:
75 parts per million
Percent increase:
23.9 %
**Calculation Details:**
1. **Increase in CO₂ levels:**
\[
389 \, \text{ppm} - 314 \, \text{ppm} = 75 \, \text{ppm}
\]
2. **Percent increase:**
\[
\left( \frac{75}{314} \right) \times 100 \approx 23.9\%
\]
Revisado y aprobado por el equipo de tutoría de UpStudy
Como
error msg
Explicar 
Simplifique esta solución The Deep Dive
The increase in carbon dioxide levels from 1959 to 2005 is calculated by subtracting the earlier measurement from the later one: 389 ppm - 314 ppm = 75 ppm. For the percent increase, we take the increase, divide it by the original value, and then multiply by 100 to get the percentage: (75 ppm / 314 ppm) × 100 ≈ 23.9%. So, the increase in carbon dioxide levels is 75 ppm, and the percent increase is approximately 23.9%.
¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde
Hazte Premium
